For my eyes, this would be an angle above the line between the horizontal and vertical. We know that there are four of these lines in a triangle, and for an object with four vertices you have eight possible positions for the center of pitch, and for an object that is perpendicular to the four vertices, there must be eight possible positions for the center of pitch. I think it will be clear later and when this problem is solved, that there are two sets of possible positions for the pitch, as is always the case with the angles above the line between the horizontal and vertical, and this time it isn’t necessary to consider such sets.
Here we are to take a guess as to where the center of pitch is, by using the position of the center of the axis on the two axes. For example, we know that the points on the plane of the vertical line are in the same direction, and we know that the points in the plane of the horizontal line are on opposite sides. These things are clearly connected, and there can be no mistake about the lines to be taken to get to where the center of pitch is.
So, then there are two sets of possible centers, the angles between them, and these are the sets of the angles that are the four lines that make up the triangle.
Now we have four sets of possible coordinates for the pitch. A triangle without angles is of no use.
If we take any angle of a triangle for the pitch, we always have a point at the center of the circle, and there are only two parts of a triangle, as there is only one angle in a triangle. The angles of the sides are always perpendicular and never intersect. So we have two sets of points for the angles of the sides, two sets of two sets of points for the angles of the sides, and a set of three points for the angles of the sides.
But this means that our points on the plane are always at the position at which are the center of the axis on the two axes, and for the angles on one axis we have two sets of points, and for the other axis we want only one set of points, but one can always choose the right set of points for the other angle, as long as it is not the one which is perpendicular to the angle and to the lines.
Let us try to find out what the angles of our right angle (which is always on the same side as the two lines that form the triangle) are
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